Sum of the first 1501 square numbers




We define square numbers as numbers that when squared will equal a whole number. Thus, the list of the first square numbers starts with 1, 4, 9, 16, and so on.

What is the sum of the first 1501 square numbers, you ask? Here we will give you the formula to calculate the first 1501 square numbers and then we will show you how to calculate the first 1501 square numbers using the formula.

The formula to calculate the first n square numbers is displayed below:

   
n(n + 1) × (2(n) + 1)
 
   
6
 

To calculate the sum of the first 1501 square numbers, we enter n = 1501 into our formula to get this:

   
1501(1501 + 1) × (2(1501) + 1)
 
   
6
 

First, calculate each section of the numerator: 1501(1501 + 1) equals 2254502 and (2(1501) + 1) equals 3003. Therefore, the problem above becomes this:

   
2254502 × 3003
 
   
6
 

Next, we calculate 2254502 times 3003 which equals 6770269506. Now our problem looks like this:

   
6770269506
 
   
6
 

Finally, divide the numerator by the denominator to get our answer:

6770269506 ÷ 6 = 1128378251

There you go. The sum of the first 1501 square numbers is 1128378251.


You may also be interested to know that if you list the first 1501 square numbers 1, 2, 9, etc., the 1501st square number is 2253001.

Sum of Square Numbers Calculator
Need the answer to a similar problem? Get the first n square numbers here.




What is the sum of the first 1502 square numbers?
Here is the next math problem on our list that we have explained and calculated for you.


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