Sum of the first 42 square numbers

We define square numbers as numbers that when squared will equal a whole number. Thus, the list of the first square numbers starts with 1, 4, 9, 16, and so on.

What is the sum of the first 42 square numbers, you ask? Here we will give you the formula to calculate the first 42 square numbers and then we will show you how to calculate the first 42 square numbers using the formula.

The formula to calculate the first n square numbers is displayed below:

		n(n + 1) × (2(n) + 1)
		6

To calculate the sum of the first 42 square numbers, we enter n = 42 into our formula to get this:

		42(42 + 1) × (2(42) + 1)
		6

First, calculate each section of the numerator: 42(42 + 1) equals 1806 and (2(42) + 1) equals 85. Therefore, the problem above becomes this:

		1806 × 85
		6

Next, we calculate 1806 times 85 which equals 153510. Now our problem looks like this:

		153510
		6

Finally, divide the numerator by the denominator to get our answer:

153510 ÷ 6 = 25585

There you go. The sum of the first 42 square numbers is 25585.

You may also be interested to know that if you list the first 42 square numbers 1, 2, 9, etc., the 42nd square number is 1764.

Sum of Square Numbers Calculator
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